Josh Wieder

In its simplest sense Typecasting is altering a computer's interpretation of data by implicitly or explicitly changing its data type; for example, by changing an `int` to a `float` and vice verse. To better understand typecasting, we must start with data types themselves. In programming languages like C, every variable has some kind of `type` that determines how the computer and the user interprets that variable. Each of these data types, for instance `int`, `long long`, `float` and `double` all have their own unique characteristics and are use to handle data types of various ranges and precision. Typecasting allows us to take a floating point number, like 3.14, and specifying the number before the decimal - 3 - by parsing it to an `int`. Let's us an example from the English language to better clarify what we mean. example.         WIND Each carefully manipulated line in the example above forms a unique symbol. However, these symbols are immediately identifiable

Problems arise with numerical expression in computing. In reality, there are an infinite number of real numbers. However there is clearly not an infinite amount of infinite memory even in the largest of super-computers, and memory that is addressable by an application is only a fraction of the total finite available memory. How to we deal with these obstacles? We will explain more in a moment. First let's overview in more detail how the C compiler handles numeral types. Consider the application below: #include <stdio.h> int main (void) {     float f = 1 / 10;     printf("%.2f\n", f);     return 0; } Here we declare a float, 1/10 which should clearly resolve to 0.1 or 0.10 since I am declaring that printf provide a float with two digits after the decimal point. However, upon complation and excecution the program will stubbornly return a value of "0.00". Why? The issue is that I am declaring a float as an operation of two integers - 1 and